exactly at the same distance from mirror as point A. Hence the image is vertical and inverted.
Since any ray coming from any point on the axis and travelling along the axis will get reflected on the axis itself, we can conclude that the base of the image is going to be on the axis. Using the knowledge, that if the object is placed vertically on the axis, the image is going to be vertical, all that we need to do, is to draw a perpendicular from point A to the axis. The intersection point is the point where the base of the image of the candle is likely to be formed. See figure-12. Hence, as shown in the diagram the image will be inverted and diminished.
Figure-12 is drawn for the case where the object is placed beyond the centre of curvature. Does this conclusion match with your observations? (Lab Activity)
Draw similar diagrams for other cases and verify that they match with your observations.
The first ray (R1 ) will start from tip of the object and run parallel to axis to get reflected so as to pass through the focal point. This one is easy to draw. The second ray that we chose for earlier ray diagrams is the ray coming from the tip of the object and going through the focal point but it is not possible as such a ray will not meet the mirror. So we must use the third ray, a ray coming from the tip of the object and going through the centre of curvature.
But that to does not seem to be possible. So we make a small change. Instead of drawing a ray from the candle tip to centre of curvature, we consider a ray that comes from the tip and goes in such a direction that it would go through the centre of curvature if extended backwards. This ray is normal to the surface and so will be reflected along the same line in opposite direction and will go through centre of curvature.