4.4g x 22.4 litres/44 g = 2.24 liters.

44 g of CO2 contain 6.023x1023 mol of CO2 4.4 g Contains - ?

4.4g x 6.023 x 1023 / 44g = 6.023 x 1022 mol

Keywords
Reactants, products, exothermic reaction, endothermic reaction Physical and chemical changes Primary or skelton Equation unit forumula, Precipitation, Co-efficient, atomic mass, standard temperature and pressure (STP) molar mass, avagadro’s number, gram molar volume.

What we have learnt
Improve Your Learning

I. Reflections on concepts
  1. What information do you get from a balanced chemical equation? (AS1 )
  2. Why should we balance a chemical equation? (AS1 )
  3. Balance the following chemical equations. (AS1)

    (a) NaOH+ H2 S0 4---> Na2 SO4 +H2O




page no.31

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