This can be made possible only when a concave lens is used (recollect image formation by refraction through a concave lens).

How can you decide the focal length of the lens to be used to correct myopia?

To correct one's Myopia, we need to select a lens which forms an image at the far point for an object at infinity. We need to select bi-concave lens to achieve this.

This image acts like an object for the eye lens. Hence the final image is formed on the retina.

Here object distance (u) is infinity and image distance (v) is equal to distance of far point

u=-infinate v=distance of far point = -D

let 'f' be the focal length of bi-concave lens

Using lens formula, 1/f=1/v-1/u

1/f1/-Df=-D

Here 'f' is negative showing that it is a concave lens.

Let us find out.

Hypermetropia

Hypermetropia is also known as "far sightedness".A person with hypermetropia can see distant objects clearly but cannot see objects at near distances, because the minimum focal length of eye lens for the person of hypermetropia is greater than 2.27 cm. In such cases, the rays coming from a nearby object, after refraction at eye lens, forms an image beyond the retina as shown in figure 6 (a).